Advanced Math Medium
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The Discriminant and Nature of Roots

Use the discriminant to determine how many real solutions a quadratic has, without solving.

Before you read
Answer first — see what you already know.

A projectile equation models when a ball reaches a certain height. How many real solutions exist?

Check your answer
Answer:

A

Before you read
Answer first — see what you already know.

For the equation modeling a chemical equilibrium, what is the discriminant?

Check your answer
Answer:

A

Theory

What Is the Discriminant?

The discriminant is the expression under the square root in the quadratic formula:

Δ=b24ac\Delta = b^2 - 4ac

It tells you how many real solutions the equation ax2+bx+c=0ax^2 + bx + c = 0 has, without solving:

DiscriminantNumber of real solutionsGraph
Δ>0\Delta > 0Two distinct real solutionsParabola crosses x-axis twice
Δ=0\Delta = 0One repeated real solutionParabola touches x-axis at vertex
Δ<0\Delta < 0No real solutionsParabola doesn't reach x-axis

-4-224-8-6-4-22468101214
(0, -4)-22
Δ > 0: two real roots
-112345-2246810
(2, 0)
Δ = 0: one repeated root (vertex on x-axis)
-3-2-1123-224681012
(0, 2)
Δ < 0: no real roots (parabola above x-axis)
Theory

Interpreting the Discriminant

Why it works: in x=b±Δ2ax = \frac{-b \pm \sqrt{\Delta}}{2a}:

- If Δ>0\Delta > 0: Δ\sqrt{\Delta} is a real positive number \to two different values from ±\pm
- If Δ=0\Delta = 0: 0=0\sqrt{0} = 0 \to ±0\pm 0 gives only one value
- If Δ<0\Delta < 0: negative\sqrt{\text{negative}} is not real \to no real solutions

Bonus: if Δ\Delta is a perfect square (1,4,9,16,...1, 4, 9, 16, ...), the solutions are rational (nice fractions). If not, they contain square roots.

Example 1

Without solving, how many real solutions does x2+3x+5=0x^2 + 3x + 5 = 0 have?

Δ=324(1)(5)=920=11\Delta = 3^2 - 4(1)(5) = 9 - 20 = -11

Δ<0\Delta < 0 \to no real solutions.

No real solutions.
Example 2

For what value of kk does x2+6x+k=0x^2 + 6x + k = 0 have exactly one solution?

One solution when Δ=0\Delta = 0.

Δ=624(1)(k)=364k=0\Delta = 6^2 - 4(1)(k) = 36 - 4k = 0

4k=364k = 36 \to k=9k = 9.

k=9k = 9

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