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Exponential Equations and Growth/Decay

Solve exponential equations, model growth and decay, and distinguish linear from exponential models.

Before you read
Answer first — see what you already know.

A culture of bacteria triples when . What is ?

Check your answer
Answer:

B

Before you read
Answer first — see what you already know.

In a doubling model, . What is ?

Check your answer
Answer:

B

Theory

Exponential vs. Linear Growth

Linear: grows by a constant amount (add the same each time)
f(x)=mx+bf(x) = mx + b

Exponential: grows by a constant factor (multiply by the same each time)
f(x)=abxf(x) = a \cdot b^x

-4-224-4-2246810
y = 0(0, 1)
y = 2ˣ: exponential growth

where:
- aa = initial value (f(0)=af(0) = a)
- bb = growth/decay factor
- b>1b > 1: growth (increasing)
- 0<b<10 < b < 1: decay (decreasing)
- xx = time or number of periods

Theory

Common Exponential Models

Population growth: P=P0(1+r)tP = P_0 \cdot (1 + r)^t (where rr = rate, e.g., 0.030.03 for 3%3\%)

Radioactive decay / half-life: A=A0(12)t/hA = A_0 \cdot \left(\frac{1}{2}\right)^{t/h} (where hh = half-life)

Doubling: A=A02t/dA = A_0 \cdot 2^{t/d} (where dd = doubling time)

Compound interest: A=P(1+rn)ntA = P\left(1 + \frac{r}{n}\right)^{nt}

FactorMeaning
1.051.055%5\% growth per period
0.900.9010%10\% decay per period
22Doubling each period
0.50.5Halving each period

Example 1

A population of 500 bacteria doubles every 3 hours. How many bacteria after 12 hours?

Doubling time =3= 3 hours, so in 1212 hours: 12/3=412/3 = 4 doublings.

P=50024=50016=8000P = 500 \cdot 2^4 = 500 \cdot 16 = 8000.

8,0008{,}000 bacteria
Example 2

A radioactive sample has a half-life of 5 years. Starting with 200g, how much remains after 15 years?

15/5=315/5 = 3 half-lives.

A=200(0.5)3=2000.125=25A = 200 \cdot (0.5)^3 = 200 \cdot 0.125 = 25g.

2525g

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