Advanced Math Medium
⏱ 25 min 📊 Medium ⭐ Premium

Factoring Advanced: ax² + bx + c and Grouping

Factor quadratics with a leading coefficient other than 1, and factor by grouping.

Before you read
Answer first — see what you already know.

A laboratory models a chemical reaction rate as . What is the factored form?

Check your answer
Answer:

A

Before you read
Answer first — see what you already know.

A structural formula involves . Which is the correct factorization?

Check your answer
Answer:

A

Theory

The AC Method (for ax2^{2} + bx + c)

When a1a \neq 1, factoring is harder. Use the AC method:

1. Multiply a×ca \times c
2. Find two numbers that multiply to acac and add to bb
3. Rewrite the middle term using those two numbers
4. Factor by grouping

  1. 2x2+7x+32x^2 + 7x + 3
  2. 2x2+6x+x+32x^2 + 6x + x + 3split middle term
  3. 2x(x+3)+1(x+3)2x(x+3) + 1(x+3)factor by grouping
  4. (2x+1)(x+3)(2x+1)(x+3)
Factoring by grouping
Example 1

Factor 2x2+7x+32x^2 + 7x + 3

AC: a×c=2×3=6a \times c = 2 \times 3 = 6

Find: two numbers that multiply to 66 and add to 77: that's 11 and 66.

Rewrite: 2x2+1x+6x+32x^2 + 1x + 6x + 3

Group: (2x2+x)+(6x+3)(2x^2 + x) + (6x + 3)

Factor each group: x(2x+1)+3(2x+1)x(2x + 1) + 3(2x + 1)

Factor out (2x+1)(2x + 1): (2x+1)(x+3)(2x + 1)(x + 3)

(2x+1)(x+3)(2x + 1)(x + 3)
(2x+1)(x+3)=2x2+6x+x+3=2x2+7x+3(2x+1)(x+3) = 2x^2 + 6x + x + 3 = 2x^2 + 7x + 3
Example 2

Factor 3x210x+83x^2 - 10x + 8

AC: 3×8=243 \times 8 = 24

Find: multiply to 2424, add to 10-10: 4-4 and 6-6.

Rewrite: 3x24x6x+83x^2 - 4x - 6x + 8

Group: (3x24x)+(6x+8)(3x^2 - 4x) + (-6x + 8)

Factor: x(3x4)2(3x4)x(3x - 4) - 2(3x - 4)

Result: (3x4)(x2)(3x - 4)(x - 2)

(3x4)(x2)(3x - 4)(x - 2)
Theory

The Trial-and-Error Method

For small coefficients, guessing and checking can be faster:

ax2+bx+c=(_x+_)(_x+_)ax^2 + bx + c = (\_ x + \_)(\_ x + \_)

The first blanks must multiply to aa, the last blanks to cc. Try combinations until the cross-products add to bb.

Example: 6x2+11x+46x^2 + 11x + 4
- 6=6×16 = 6 \times 1 or 3×23 \times 2
- 4=4×14 = 4 \times 1 or 2×22 \times 2
- Try (3x+4)(2x+1)(3x + 4)(2x + 1): 3x1+42x=3x+8x=11x3x \cdot 1 + 4 \cdot 2x = 3x + 8x = 11x

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