Algebra Medium
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Interpreting Linear Models in Context

Interpret slope, y-intercept, and solutions of linear equations in real-world contexts.

Before you read
Answer first — see what you already know.

The equation gives the monthly cost (in dollars) of a water bill, where is water usage in gallons. What does represent?

Check your answer
Answer:

C

Before you read
Answer first — see what you already know.

A car's value is modeled by , where is value in dollars and is years since purchase. What is the best interpretation of ?

Check your answer
Answer:

B

Theory

The Big Three: Slope, Y-Intercept, and X-Intercept in Context

When a linear equation models a real situation (y=mx+by = mx + b):

MathReal-world meaning
Slope (mm)The rate of change — how much yy changes for each 1-unit increase in xx
Y-intercept (bb)The starting value — the value of yy when x=0x = 0
X-interceptThe break-even or end point — the value of xx when y=0y = 0

-6-4-2246-6-4-2246
(0, 200)
Monthly savings: $15/month starting at $200

The SAT tests your ability to connect these math concepts to their meaning in the problem's story.

Example 1

P=12t480P = 12t - 480 models a company's monthly profit PP (dollars) based on tt shirts sold.

Interpret the slope, y-intercept, and find the x-intercept.

Slope = 12: Each additional shirt sold increases profit by $12\$12 (the profit per shirt).

Y-intercept = -480: When 0 shirts are sold, the company loses $480\$480 (fixed costs).

X-intercept: 0=12t4800 = 12t - 480 \to t=40t = 40. The company needs to sell 4040 shirts to break even.

Slope = 12/shirt,yintercept=12/shirt, y-intercept = -480 (fixed costs), break-even at 40 shirts
Theory

Choosing the Right Model

Sometimes the SAT gives you a scenario and asks which equation best models it. Look for:

1. Is there a starting value? \to That's bb
2. Is there a rate per unit? \to That's mm
3. Is the quantity increasing or decreasing? \to Positive or negative mm

Common model types:
- Cost models: C=(cost per unit)x+(fixed cost)C = \text{(cost per unit)} \cdot x + \text{(fixed cost)}
- Distance/motion: d=rt+d0d = rt + d_0
- Depreciation: V=V0rtV = V_0 - rt (value decreases)
- Population/growth: P=P0+rtP = P_0 + rt (linear growth)

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2 more sections including examples, practice problems, and step-by-step solutions.

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