Algebra Medium
⏱ 20 min 📊 Medium ⭐ Premium

Literal Equations (Solving for a Variable)

Rearrange formulas and equations with multiple variables to isolate a specific variable.

Before you read
Answer first — see what you already know.

The area of a rectangular banner is given by . A designer knows the area and base , and needs to find the height . Which expression gives in terms of and ?

Check your answer
Answer:

B

Before you read
Answer first — see what you already know.

A running track's circumference is . A coach measures the circumference and needs to find the radius. Which equation gives in terms of ?

Check your answer
Answer:

C

Theory

What Is a Literal Equation?

A literal equation is an equation with two or more variables. Instead of solving for a number, you solve for one variable in terms of the others.

You already know many literal equations — they're just formulas:
- Area of a rectangle: A=lwA = lw
- Distance formula: d=rtd = rt
- Slope-intercept form: y=mx+by = mx + b
- Temperature conversion: F=95C+32F = \frac{9}{5}C + 32

The method is exactly the same as solving a regular equation: use inverse operations to isolate the target variable.

  1. A=12bhA = \frac{1}{2}bh
  2. 2A=bh2A = bhmultiply by 2
  3. h=2Abh = \frac{2A}{b}divide by b
Solving for h in the area formula
Theory

Step-by-Step Method

To solve a literal equation for a variable:
1. Identify the variable you're solving for
2. Treat every other letter as if it were a number
3. Use inverse operations (same rules as always) to isolate your target
4. Check: the target variable should be alone on one side

Example 1

Solve d=rtd = rt for tt

We want tt alone. Currently tt is multiplied by rr.

Divide both sides by rr:

t=drt = \frac{d}{r}

t=drt = \frac{d}{r}
Example 2

Solve y=mx+by = mx + b for xx

We want xx alone.

Step 1: Subtract bb from both sides:

yb=mxy - b = mx

Step 2: Divide both sides by mm:

x=ybmx = \frac{y - b}{m}

x=ybmx = \frac{y - b}{m}
Example 3

Solve P=2l+2wP = 2l + 2w for ww

We want ww alone.

Step 1: Subtract 2l2l from both sides:

P2l=2wP - 2l = 2w

Step 2: Divide both sides by 22:

w=P2l2w = \frac{P - 2l}{2}

w=P2l2w = \frac{P - 2l}{2}
Example 4

Solve F=95C+32F = \frac{9}{5}C + 32 for CC

Step 1: Subtract 3232:

F32=95CF - 32 = \frac{9}{5}C

Step 2: Multiply by 59\frac{5}{9} (the reciprocal):

C=5(F32)9C = \frac{5(F - 32)}{9}

C=5(F32)9C = \frac{5(F - 32)}{9}

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