ACT Math Hard
⏱ 15 min 📊 Hard ⭐ Premium

Unit Circle and Trig Identities (Introduction)

The unit circle has radius 1 centered at the origin. A point at angle has coordinates . Key angles (memorize!): | | | | |---|---|---| | 0° | 1 | 0 | | 30°…

Before you read
Answer first — see what you already know.

What is ?

Check your answer
Answer:

D

Before you read
Answer first — see what you already know.

What is ?

Check your answer
Answer:

B

Theory

The Unit Circle

The unit circle has radius 1 centered at the origin. A point at angle θ\theta has coordinates (cos⁡θ,sin⁡θ)(\cos\theta, \sin\theta).

-6-4-2246-6-4-2246
r = 5(0, 0)
The unit circle: radius = 1, center at origin

Key angles (memorize!):

θ\thetacos⁡θ\cos\thetasin⁡θ\sin\theta
0°0°1100
30°30°32\frac{\sqrt{3}}{2}12\frac{1}{2}
45°45°22\frac{\sqrt{2}}{2}22\frac{\sqrt{2}}{2}
60°60°12\frac{1}{2}32\frac{\sqrt{3}}{2}
90°90°0011
180°180°−1-100
270°270°00−1-1
360°360°1100

r = 545°45°
45° angle: sin(45°) = √2/2, cos(45°) = √2/2

In other quadrants, use reference angles and the sign rules (ASTC: All Students Take Calculus →\to which trig functions are positive in each quadrant).

Example 1

Find sin⁡(150°)\sin(150°) and cos⁡(150°)\cos(150°).

Reference angle: 180°−150°=30°180° - 150° = 30°

Quadrant II: sin is positive, cos is negative

sin⁡(150°)=sin⁡(30°)=12\sin(150°) = \sin(30°) = \frac{1}{2}

cos⁡(150°)=−cos⁡(30°)=−32\cos(150°) = -\cos(30°) = -\frac{\sqrt{3}}{2}

sin⁡(150°)=12\sin(150°) = \frac{1}{2}, cos⁡(150°)=−32\cos(150°) = -\frac{\sqrt{3}}{2}
Theory

Key Trig Identities

Pythagorean: sin⁡2θ+cos⁡2θ=1\sin^2\theta + \cos^2\theta = 1

Reciprocal:
- sec⁡θ=1cos⁡θ\sec\theta = \frac{1}{\cos\theta}
- csc⁡θ=1sin⁡θ\csc\theta = \frac{1}{\sin\theta}
- cot⁡θ=1tan⁡θ=cos⁡θsin⁡θ\cot\theta = \frac{1}{\tan\theta} = \frac{\cos\theta}{\sin\theta}

Quotient: tan⁡θ=sin⁡θcos⁡θ\tan\theta = \frac{\sin\theta}{\cos\theta}

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